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hackercup / 2014 /finals /lunch_at_facebook.md
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2014 Problems
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What's the best thing about working at Facebook? It's hard to say, but the
free food doesn't hurt. Every day there are long lines for food, and sometimes
guests visit the campus, as hungry as everybody else. It pays to be a good
host, so sometimes we'll let guests cut ahead in the line. But obviously
nobody wants to miss out on delicious Facebook food.
Every day, **N** Facebook employees are lined up for lunch, and every day
**M** visitors come to the campus looking for food. Each person has an
appetite **Ai**, which is a positive integer. Curiously, no two people have
the same appetite.
If people with large appetites eat first, there's a concern that the food
might run out before the people at the back get to eat, so it's ideal to have
people with smaller appetites further ahead in the line. With this in mind,
we'd like to squeeze all of the guests into the lunch line as efficiently as
possible.
We define the _unsuitableness_ of a line as the number of pairs of people in
the line, **Pi** and **Pj**, such that **Pi** is ahead of **Pj** in the line,
and **Pi** has a larger appetite than **Pj**. Your task is to find a way to
get all the visitors into the lunch line such that the unsuitableness of the
resulting line is minimized. The employees that are standing in line won't
change order, but you can put guests in any place you want.
### Input
The first line contains an integer **T**, the number of test cases.
Each test case has three lines:
A line with **N** and **M**.
A line with **N** integers, the appetites of the employees in order, beginning
with the first employee.
A line with **M** integers, the appetites of the visitors.
### Output
For each test case _i_, output "Case #i: " followed by the minimum possible
unsuitableness of the resulting line.
### Constraints
1 ≤ **T** ≤ 20
1 ≤ **N** ≤ 105
1 ≤ **M** ≤ 105
1 ≤ **Ai** ≤ 109
### Explanation of Sample
For the first test case the optimal lunch line has the following appetites in
order: 1, 2, 3, 4
For the second test case the optimal lunch line is: 1, 2, 4, 7, 5, 3